WebSep 30, 2016 · When you insert the numbers on TStringList (and convert it to Strings), use '0' on left part. 00000018 00000020 00000003 00000044 00000053 Change the Sorted property to True and let the TStringList make the work. Now the numbers are sorted. 00000003 00000018 00000020 00000044 00000053 WebJul 9, 2024 · Is the number in the string required to be a number that can be stored by a Delphi numeric type? Nineteen quintillion is a number, but it won't fit in any Delphi integral type. ... One hundred-thousandth is a number, but no Delphi numeric type can hold it. Rob Kennedy almost 12 years @Jørn, it was a serious question. I'm just trying to stave ...
Delphi: count number of times a string occurs in another string
WebMay 27, 2024 · For efficiency, things you want to avoid are a) repeatedly scanning the same characters over and over and b) copying one or both strings. Since D7, Delphi has included a PosEx function: function PosEx (const SubStr, S: string; Offset: Cardinal = 1): Integer; Description PosEx returns the index of SubStr in S, beginning the search at Offset. WebNov 26, 2024 · stucked on Delphi 10.3.1. Sennar. New member; Posts: 8; Re: Extract numbers from a string ... signed numbers or multiple numbers in one string. To handle the first two, a simple change to the constant 'n' by adding '-', '+' and '.' would improve matters . Code: Pascal . const. n ... the giraffe who got in a knot
delphi - How to find and count a word in a text string? - Stack …
WebFeb 4, 2024 · Description: Removes Count characters from a string S, starting at Index. Delphi leaves the string unchanged if Index is not positive or greater than the … WebMay 25, 2024 · function FindItem (const List, Item: string): Boolean; var SArr: TArray; S: string; begin Result := False; //Separators could also be a parameter SArr := List.Split ( [',']); for S in SArr do begin //use S.Trim if needed //use AnsiSameText (S, Item) for case insensitive check if Item = S then Exit (True); end; end; WebAug 6, 2007 · I need to extract the letter X and the numbers 78.54, change X to B, perform a calculation and then pass back to the origional string. To get this; N230G01B90.0Y34.75f300. While the code I wrote below works fine, the value of X may not be followed by a Y value (which I am using to mark the end of the X value) or any other … the arrival christopher nevinson