WebJul 10, 2016 · 2.5 mL First lets get the units the same for the suspension (in mg) and the required amount of ampicillin (in g): 1 g = 1000 mg -> 0.125 g = 125 mg For easy calculation and for better understanding of what you are doing, it is best to then calculate how many mg is in 1 mL: (250 mg) / (5.0 mL)= (50 mg)/(1 mL) So 1 mL of the solution … WebApr 6, 2024 · Dissolve 9.31 g of #Na_2S_2O_3 * 5H_2O# into 250mL water.. Molarity is moles/Liter. 0.150 M in 250mL is ¼ of 0.150 moles/L, or 0.0375 moles/0.25L. #Na_2S_2O_3 * 5H_2O# just has the extra mass (moles) of water to consider. That is irrelevant to this problem because we are already given the molar mass for the compound.
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WebFenix Community Portal - Fenix Marine Services WebDec 21, 2024 · Explanation: The concentration can be expressed as molarity as follows: Molarity = NaCl moles / liters of solution We are already given the number of moles (0.150 mol) so we need to calculate the liters of solution. We convert mL to L: 250.0 mL * = 0.250 L Now we can calculate the molarity of the NaCl solution: inconsistent line endings sql server
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WebFerroxcube 846T250-3E2A, un-painted. We have found the best core, with low loss and high permeability for pulse, linear and broadband transformers and power supplies. EMI … WebMar 14, 2024 · Find the ph of a 0.250 m solution of nac2h3o2. (the ka value of hc2h3o2 is 1.80×10−5). express your answer numerically to four significant figures. See answer Advertisement Dejanras Answer is: pH value of solution of NaC₂H₃O₂ is 9.07. Chemical reaction: C₂H₃O₂⁻ + H₂O ⇄ HC₂H₃O₂ + OH⁻. Ka (HC₂H₃O₂) = 1,8·10⁻⁵. Ka · Kb = Kw. WebJan 11, 2016 · Let's assume for a second that you're not familiar with the equation for dilution calculations.. What would your approach be here? As you know, diluting a solution means keeping the number of moles of solute constant while increasing the total volume of the solution by adding more solvent. Since molarity is defined as moles of solute per … inconsistent naming convention