WebApr 13, 2024 · CuNiSi alloys are widely used for lead frames and connectors due to the combination of high strength and high electrical conductivity. In this work, the microstructures, properties and precipitation behaviors of cryo-rolled CuNiSi alloys with different Cr additions were investigated. The results show that the microstructures of cryo … WebThe Function F (X) = Tan X is Discontinuous on the Set (A) {N π : N ∈ Z} (B) {2n π : N ∈ Z} (C) { ( 2 N + 1 ) π 2 : N ∈ Z } (D) { N π 2 : N ∈ Z } Department of Pre-University Education, Karnataka PUC Karnataka Science Class 12. Textbook Solutions 13651. MCQ ...
The function given by f(x) = tan x is discontinuous on the set - Toppr
WebJul 9, 2015 · The formula you used to define f(x) by is not defined at the points where you say the function is discontinuous. You need to define the function at those points before talking about continuity or discontinuity at those points. WebIf p ( )x x 2 x k and if the remainder is 12 when p ( )x is divided by x 1,then k (A) 2 (B) 3 (C) 6 (D) 11 (E) 13 When the area in square units of an expanding circle is increasing twice as fast as its radius in linear units, the radius is hotels near nccu in durham nc
Discontinuity Calculator: Wolfram Alpha
WebThe points of discontinuity of tanx are A nπ,n∈I B 2nπ,n∈I C (2n+1) 2π,n∈I D None of the above Medium Solution Verified by Toppr Correct option is C) Let f(x)=tanx The points of discontinuity of f(x) are those points where tanx is infinite. This gives tanx=∞ ie tanx=tan 2π x=(2n+1) 2π,n∈I Was this answer helpful? 0 0 Similar questions WebFeb 1, 2016 · You are correct in that the denominator x^2+1 doesn't become zero. However, tan (x) can still be undefined. Remember that tan x = sin (x)/cos (x), so you need to determine when the cos x = 0. Recall from the unit circle that this would be when x = pi/2, 3pi/2, 5pi/2, etc. So the function would be discontinuous at those x values. I hope this helps. WebJul 9, 2024 · Pre-Calculus For Dummies. If the function factors and the bottom term cancels, the discontinuity at the x-value for which the denominator was zero is removable, so the graph has a hole in it. After canceling, it leaves you with x – 7. Therefore x + 3 = 0 (or x = –3) is a removable discontinuity — the graph has a hole, like you see in ... limetown finale